12x-2[3(x+1)]=2(x+3)

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Solution for 12x-2[3(x+1)]=2(x+3) equation:


Simplifying
12x + -2[3(x + 1)] = 2(x + 3)

Reorder the terms:
12x + -2[3(1 + x)] = 2(x + 3)
12x + -2[(1 * 3 + x * 3)] = 2(x + 3)
12x + -2[(3 + 3x)] = 2(x + 3)
12x + [3 * -2 + 3x * -2] = 2(x + 3)
12x + [-6 + -6x] = 2(x + 3)

Reorder the terms:
-6 + 12x + -6x = 2(x + 3)

Combine like terms: 12x + -6x = 6x
-6 + 6x = 2(x + 3)

Reorder the terms:
-6 + 6x = 2(3 + x)
-6 + 6x = (3 * 2 + x * 2)
-6 + 6x = (6 + 2x)

Solving
-6 + 6x = 6 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-6 + 6x + -2x = 6 + 2x + -2x

Combine like terms: 6x + -2x = 4x
-6 + 4x = 6 + 2x + -2x

Combine like terms: 2x + -2x = 0
-6 + 4x = 6 + 0
-6 + 4x = 6

Add '6' to each side of the equation.
-6 + 6 + 4x = 6 + 6

Combine like terms: -6 + 6 = 0
0 + 4x = 6 + 6
4x = 6 + 6

Combine like terms: 6 + 6 = 12
4x = 12

Divide each side by '4'.
x = 3

Simplifying
x = 3

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